A force ~F = Fx ˆı+Fy ˆ acts on a particle that
undergoes a displacement of ~s = sx ˆı + sy ˆ
where Fx = 8 N, Fy = −4 N, sx = 5 m, and sy = 1 m.
Find the work done by the force on the
Answer in units of J.
x^2 + y^2 = z^2
Work = (Force)(Distance)(cos(theta))
The Attempt at a Solution
I found the magnitude of Force by squaring each component
F = (8)^2 + (-4)^2 = 8.9442N
I found the magnitude of Distance by squaring each component
F = (5)^2 + (1)^2 = 5.099m
I then created a triangle to find theta, using distance for my triangle sides.
tan(theta) = 1/5 so theta = inverse tan(1/5). I then got a theta of 11.310.
I plugged my force, distance and theta into the Work formula but I'm not getting the right answer.
W = (8.9442N)(5.099)(cos(11.310))
W = 44.721 Joules
THIS IS NOT THE RIGHT ANSWER. WHAT AM I DOING WRONG. PLEASE HELP ME.
Find the angle between ~F and ~s.
Answer in units of ◦.