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## Homework Statement

A force ~F = Fx ˆı+Fy ˆ acts on a particle that

undergoes a displacement of ~s = sx ˆı + sy ˆ

where Fx = 8 N, Fy = −4 N, sx = 5 m, and sy = 1 m.

Find the work done by the force on the

particle.

Answer in units of J.

## Homework Equations

x^2 + y^2 = z^2

Work = (Force)(Distance)(cos(theta))

## The Attempt at a Solution

I found the magnitude of Force by squaring each component

F = (8)^2 + (-4)^2 = 8.9442N

I found the magnitude of Distance by squaring each component

F = (5)^2 + (1)^2 = 5.099m

I then created a triangle to find theta, using distance for my triangle sides.

tan(theta) = 1/5 so theta = inverse tan(1/5). I then got a theta of 11.310.

I plugged my force, distance and theta into the Work formula but I'm not getting the right answer.

W = (8.9442N)(5.099)(cos(11.310))

W = 44.721 Joules

THIS IS NOT THE RIGHT ANSWER. WHAT AM I DOING WRONG. PLEASE HELP ME.

## Homework Statement

Find the angle between ~F and ~s.

Answer in units of ◦.