Need Help With Gradient (Spherical Coordinates)

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Homework Help Overview

The discussion revolves around finding the gradient of the function f(r) = rcos(θ) in spherical coordinates. Participants are exploring the application of the gradient operator in this specific coordinate system.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of partial derivatives with respect to spherical coordinates and express uncertainty about how to incorporate the unit vectors (hat notation) into the gradient expression.

Discussion Status

Some participants have provided calculations for the partial derivatives and have begun to formulate the gradient expression. There is a recognition of the similarities between spherical and Cartesian coordinates, although questions remain about the transition between the two systems.

Contextual Notes

There is an emphasis on understanding the notation and structure of the gradient in spherical coordinates, with some participants questioning the differences compared to Cartesian coordinates. The original poster expresses confusion about the initial steps in the process.

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Homework Statement


Find te gradient of the following function f(r) = rcos(##\theta##) in spherical coordinates.

Homework Equations


\begin{equation}
\nabla f = \frac{\partial f}{\partial r} \hat{r} + (\frac{1}{r}) \frac{\partial f}{\partial \theta} \hat{\theta} + \frac{1}{rsin\theta} \frac{\partial f}{\partial \phi} \hat{\phi}
\end{equation}

The Attempt at a Solution


I know that z = rcos##\theta## But I don't know where to go from there since I don't see any ##\hat{r}##, ##\hat{\theta}##, ##\hat{\phi}##
 
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Do you know how to calculate ## \frac{\partial f}{\partial r} ##,## \frac{\partial f}{\partial \theta} ## and ## \frac{\partial f}{\partial \phi} ##?
 
ShayanJ said:
Do you know how to calculate ## \frac{\partial f}{\partial r} ##,## \frac{\partial f}{\partial \theta} ## and ## \frac{\partial f}{\partial \phi} ##?

if you're asking if I know how to take partial derivatives, then yes. The issue lies in I don't know where to begin since there is ##\hat{r}##, ##\hat{\theta}##, ##\hat{\phi}## in the equation.
 
Its just like gradient in the Cartesian coordinates. You calculate ## \frac{\partial f}{\partial x} ##,etc. and assume they are components of a vector field. So you have ## \vec \nabla f=(\frac{\partial f}{\partial x},\frac{\partial f}{\partial y},\frac{\partial f}{\partial z})=\frac{\partial f}{\partial x}\hat x+\frac{\partial f}{\partial y}\hat y+\frac{\partial f}{\partial z}\hat z ##.
What is so different about spherical coordinates?
 
So would it be:

\begin{equation}
\begin{split}
f(r) = rcos(\theta) \\
\frac{\partial f}{\partial r} = cos\theta \\
\frac{\partial f}{\partial \theta} = - rsin \theta \\
\frac{\partial f}{\partial \phi} = 0
\end{split}
\end{equation}
So the gradient is
\begin{equation}
cos\theta \ \hat{r} + -sin\theta \ \hat{\theta}
\end{equation}

Is this correct?
 
ShayanJ said:
Yes, that's correct.

Thank you, very much! :)
 

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