- #1

russjai

- 7

- 0

**1. Evaluate the integrals**a.) (x^2+6)/(√x) dx (between 1 and 4)

ans = 24.4

b.) (2x)/(√1+2x) dx (between 0 and 4)

ans = 20/3

**2.) The position function (in meters) of a particle is given by s=t^3-10.5t^2-2t t>0 . When does the particle reach a velocity of 52 m/s?**

ans = 9

**3. The Attempt at a Solution for Q.2**

started by taking the derivative of s=t^3-10.5t^2-2t, Which gives Sv=3t^2-21t-2 .

I seem to get the wrong answer using algebra to solve t for 52= 3t^2-21t-2 .

Thanks in advance for your help.

Cheers