Need some direction please. Thermodynamics.

In summary, the conversation discusses the problem of determining the temperature at which an aluminum wing would be 0.05m shorter. The equation used to solve this problem is ∆T = ∆l / α x l, where ∆T is the temperature difference, ∆l is the change in length, α is the coefficient of linear expansion, and l is the initial length. After some trial and error, the correct temperature is found to be -46.667*C. The conversation also mentions the difficulties and doubts of the person asking the question due to their lack of expertise in physics.
  • #1
travism123
9
0

Homework Statement



Aluminum wing is 30m long at 20*c

At what temperature would the wing be .05m shorter?

The coefficient for linear expansion of aluminum is (16 x 10^-6/c)


I have no idea how to do this. I don't want an answer. Just an equation or a hint on what to do. Thank you very much.
 
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  • #2
What is the relation between the initial length , final length , coefficient of linear expansion and temperature difference?
 
  • #3
I have no idea.
 
  • #4
Where did you get that coefficient? "16 x 10^-6/c" Are you sure of the "units"? What does "/c" mean? You might want to check that.
 
  • #5
Sorry,
I messed up the coefficient. It's 25 x 10^-6/*C
 
  • #6
I'm sorry if I sound stupid not being able to figure this question out. The truth is I probably have no business being in a physics class. I'm going to school to be a therapist and am taking this class to fill a science requirement. I'm sure there are easier classes I could've taken, but a few months before the semester started I saw that documentary The Elegant Universe and thought hmm... physics looks fun. That blasted Brian Greene and his easy to understand explanations!
 
  • #7
Does this look right?

Aluminum wing is 30m at 20*C. At what temp would it be .05m shorter.
∆T = ∆l / α x l
∆T = -.05m/(25 x 10-6/*C) x 30m
∆T = -66.667
The wing would be at -46.667*C to be .05m shorter.
 
  • #8
Yes.
 
  • #9
Thank you very much.
 

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