Need some direction please. Thermodynamics.

AI Thread Summary
To determine the temperature at which a 30m aluminum wing would be 0.05m shorter, the coefficient of linear expansion for aluminum is used. The corrected coefficient is 25 x 10^-6/°C. The equation ∆T = ∆l / (α x l) is applied, where ∆l is the change in length, α is the coefficient, and l is the original length. The calculation shows that the wing would need to be at approximately -46.67°C to achieve the desired contraction. This approach effectively illustrates the relationship between temperature change and material expansion.
travism123
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Homework Statement



Aluminum wing is 30m long at 20*c

At what temperature would the wing be .05m shorter?

The coefficient for linear expansion of aluminum is (16 x 10^-6/c)


I have no idea how to do this. I don't want an answer. Just an equation or a hint on what to do. Thank you very much.
 
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What is the relation between the initial length , final length , coefficient of linear expansion and temperature difference?
 
I have no idea.
 
Where did you get that coefficient? "16 x 10^-6/c" Are you sure of the "units"? What does "/c" mean? You might want to check that.
 
Sorry,
I messed up the coefficient. It's 25 x 10^-6/*C
 
I'm sorry if I sound stupid not being able to figure this question out. The truth is I probably have no business being in a physics class. I'm going to school to be a therapist and am taking this class to fill a science requirement. I'm sure there are easier classes I could've taken, but a few months before the semester started I saw that documentary The Elegant Universe and thought hmm... physics looks fun. That blasted Brian Greene and his easy to understand explanations!
 
Does this look right?

Aluminum wing is 30m at 20*C. At what temp would it be .05m shorter.
∆T = ∆l / α x l
∆T = -.05m/(25 x 10-6/*C) x 30m
∆T = -66.667
The wing would be at -46.667*C to be .05m shorter.
 
Yes.
 
Thank you very much.
 

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