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An alpha particle of 3.2 x 10^-19C (to the power -19) accelerates from rest between two oppositely charged plates starting from the +ve plate. The electric field between the plates is uniform and equal to 39000 N/C. The distance between the plates is 4.50 x 10^-3m (to the power -3).
a) calculate the force on the alpha particle.
I put 1.6 x 10^-19 (power -19) x 39000 = 6.24 x 10^-15 (power -15)
b) How much work is done by the electric field in accelerating the particle the full distance between the plates.
I put (6.24 x 10^-15) x (4.50 x 10^-3) = 2.808 x 10^-17.
Are my calculations correct?
Also i must state c) by how much does the alpha particle's KE increase? I know the formula is half MV squared but I am not sure which figures i must use
and d) by how much does the alpha particle's PE change? I know this formula is MGH but again I am not sure which figures to use
a) calculate the force on the alpha particle.
I put 1.6 x 10^-19 (power -19) x 39000 = 6.24 x 10^-15 (power -15)
b) How much work is done by the electric field in accelerating the particle the full distance between the plates.
I put (6.24 x 10^-15) x (4.50 x 10^-3) = 2.808 x 10^-17.
Are my calculations correct?
Also i must state c) by how much does the alpha particle's KE increase? I know the formula is half MV squared but I am not sure which figures i must use
and d) by how much does the alpha particle's PE change? I know this formula is MGH but again I am not sure which figures to use