Negative and positive work - Question

  • Context: Undergrad 
  • Thread starter Thread starter SigmaScheme
  • Start date Start date
  • Tags Tags
    Negative Positive Work
Click For Summary
SUMMARY

The discussion centers on the concept of work in physics, specifically regarding the application of forces on a mass moving upward. When a mass is accelerated upward by 2G and then subjected to a force of \(\frac{1}{2}G\) while still moving upward but decelerating, the individual applying the force does positive work. This is because the direction of the applied force aligns with the displacement of the mass, despite the mass's deceleration. In contrast, the net work done on the mass is negative due to the opposing gravitational force.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concept of work and energy in physics
  • Knowledge of force vectors and their components
  • Basic grasp of acceleration and its effects on motion
NEXT STEPS
  • Study the principles of work-energy theorem in classical mechanics
  • Explore vector decomposition in physics to analyze forces
  • Learn about the effects of gravitational forces on moving objects
  • Investigate the relationship between force, displacement, and work done
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in understanding the principles of work and energy in motion.

SigmaScheme
Messages
4
Reaction score
0
I accelerate a mass upward by 2G (2×force of gravity) over some change in height Δh_{1}, then I apply only \frac{1}{2}G over some other change in height Δh_{2}.

If, over Δh_{2}, the mass still moving upward (but accelerating downwards), am I doing positive work over Δh_{2} even though the mass is accelerating in the opposite direction to the force I am applying?THANKS!
 
Physics news on Phys.org
No-- the work depends on the sign of the force (and so the acceleration), times the sign of the displacement. So switching the sign of one or the other (but not both) will change the sign of the work.
 
OK, thanks, So what about MY work alone due to the force I am applying, rather than the work due to the net force.

MY force and x ARE in the same direction (although the mass is slowing down). Splitting the question into components, am I alone doing positive work regardless of net work - even though the mass is slowing down?
 
SigmaScheme said:
am I alone doing positive work regardless of net work - even though the mass is slowing down?
Yes, you are still doing positive work on the object. The Earth is doing negative work. And the net work done on it is negative.
 

Similar threads

Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 27 ·
Replies
27
Views
4K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 54 ·
2
Replies
54
Views
6K
  • · Replies 15 ·
Replies
15
Views
1K
  • · Replies 30 ·
2
Replies
30
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K