Hi, Iam reading horowitz and hill and came through this paragraph in section 2.03 Emitter follower : Notice (Section 2.01, rule 4) that in an emitter follower the npn transistor can only "source" current. For instance, in the loaded circuit shown in Figure 2.8 the output can swing to within a transistor saturation voltage drop of (about +9.9v) but it cannot go more negative than -5 volts. That is because on the extreme negative swing, the transistor can do no more than turn off, which it does at -4.4 volts input (-5v output). How will the transistor turn off at -4.4, it should have turned off much before right ? Am i missing basics of it ?