Two point charges q1 = 4.90×10-5 C and q2 = 2.45×10-4 C are separated by a distance d = 0.10 m. Compute their net electric field E (x) as a function of x for the following positive and negative values of x, taking E to be positive when the vector E points to the right and negative when E points to the left.What is E(-0.100)?
I tried the following equations, but I couldn't get any to work for any of the values of x:
E(x<0)= -k [(Q1/x^2)+(Q2/(d-x)^2]
E(0<x<d)= k [(Q1/x^2)-(Q2/(d-x)^2]
E(d<x)= k [(Q1/x^2)+(Q2/(d-x)^2]
The Attempt at a Solution
E(-0.100)= -9e9 [(4.90e-5/-0.01)+(2.45e4/0.04)] = -1.1e7 N/C
This is being marked incorrect and I don't know what I'm doing wrong. I've attempted multiple times with no luck.