Net Electric Field Defined at a Point with Charges Present

Click For Summary

Discussion Overview

The discussion revolves around the definition and calculation of the electric field at a point where charges are present, particularly in the context of Gauss's law and charge distributions. Participants explore the implications of introducing a test charge in the vicinity of existing charges and the nature of electric fields in macroscopic versus microscopic contexts.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants question how the electric field can be defined at a point where charges are present, referencing Gauss's law.
  • Others propose that the electric field is defined as the force per unit charge on a test charge, but this raises concerns about the presence of other charges.
  • It is noted that a test charge is considered to have a vanishingly small charge to avoid interference with the ambient field.
  • Some participants discuss the implications of calculating the electric field of a charge distribution in matter, particularly at the exact position of a charge.
  • There is a suggestion that an infinitesimal piece of a charge distribution does not exert a force on itself, but the surrounding charges do contribute to the net electric field.
  • One participant emphasizes that the concept of volume density of charge is a macroscopic average and that electric fields calculated from this perspective may not reflect microscopic realities.
  • Another participant raises a question about the derivation of the electric field inside a solid sphere using Gauss's law, questioning the meaning of the field in that context and the implications of removing charge for calculations.

Areas of Agreement / Disagreement

Participants express multiple competing views regarding the definition and calculation of electric fields in the presence of charges. The discussion remains unresolved, with no consensus on how to reconcile the presence of charges with the definition of the electric field.

Contextual Notes

Participants highlight limitations in understanding the electric field at points occupied by charges, noting that classical electrodynamics may not fully address these issues without considering quantum effects. The discussion also touches on the idealization of charge distributions for ease of calculation.

pardesi
Messages
337
Reaction score
0
consider a region where charge is distributed then we have by gauss' law
\nabla \cdot \vec E =\frac{\rho}{\epsilon_{o}}
what is \vec E here.if it is the net electric field then how is that the field is defined at a point where charges are itself present
 
Last edited by a moderator:
Physics news on Phys.org
pardesi+edits said:
consider a region where charge is distributed then we have by gauss' law
\nabla \cdot \vec E =\frac{\rho}{\epsilon_{o}}
what is \vec E here.if it is the net electric field then how is that the field is defined at a point where charges are itself present


The electric field is defined as the force/charge ratio on a small "test charge", see for instance

http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elefie.html
 
so how come u introduce a test charge at a place where ther i s already presence of charge
 
Electric and Magnetic fields in matter are the macroscopic fields ... which means the average over regions large enough to contain many atoms ... The actual microscopic fields will fluctuate strongly inside matter ...

This is what I understand from Griffiths.
 
pardesi said:
so how come u introduce a test charge at a place where ther i s already presence of charge

because by definition a test charge's charge is vanishingly small. you need this to argue that the field of the charge itself doesn't interfere with the ambient field at that point.
 
ice109 said:
because by definition a test charge's charge is vanishingly small. you need this to argue that the field of the charge itself doesn't interfere with the ambient field at that point.

I think what the issue is trying to get at is that if we calculate the electric field of a charge distribution in matter then what happens to E at the exact position where we have the charge (just based on classical electrodynamics).
 
Last edited:
A charge does not exert a net electric force on itself. Otherwise a charge could set itself in motion by way of its own electric field. Therefore, when calculating the electric force on a particular charge, we include only the fields produced by the other surrounding charges.

ansrivas said:
if we calculate the electric field of a charge distribution in matter then what happens to E at the exact position where we have the charge

An infinitesmal piece of the charge distribution does not exert an electric force on itself. However, the remainder of the charge distribution does. A distribution of (say) positive charge flies apart by mutual repulsion unless there are other forces holding it together.
 
Last edited:
ansrivas said:
I think what the issue is trying to get at is that if we calculate the electric field of a charge distribution in matter then what happens to E at the exact position where we have the charge (just based on classical electrodynamics).
yes this is my question and not whether the charge exerts force on itself or not.
if we have a continious charge distribution then hoe is that w e find the net field at a point(what is the charge we have to leave out)
 
jtbell said:
An infinitesmal piece of the charge distribution does not exert an electric force on itself. However, the remainder of the charge distribution does. A distribution of (say) positive charge flies apart by mutual repulsion unless there are other forces holding it together.


I tried to be clear that we are not talking about test charges here at all. The issue is we all know that charge is quantized. So what does one exactly mean by volume density of charge. This is made clear by the question here where we are discussing the field at the very point we have an electron sitting. So as I said without getting into Quantum effects what does classical electrodynamics have to say about this.

So a charge distribution having a volume density \rho is really a macroscopic average density and the electric field that we calculate can only be a macroscopic average. The field calculated using a volume distribution cannot be expected to be uniform in the tiniest scale. This is an idealization to enable ease of calculation.

Griffiths talks about this exact problem in his book "Intro. to electrodynamics". Just look for "macroscopic" in the index if you have the book.
 
  • #10
yes exactly that's what my point is also another question .any book has a derivation of a field inside a solid sphere by using gauss's law on a concentric sphere .But what's the meaning of field inside the sphere .yes one could argue that if we remove some charge and then calculate the field the'r but will that give u the actual net field it does but how do we know that .
for ex had that distribution be surface charge clearly we would have got only half of our desired value
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
995
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
480
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
415
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 29 ·
Replies
29
Views
2K