Net Electric Field due to 2 different charges

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SUMMARY

The discussion focuses on determining the point along the line connecting two charges, 0.600 nC and 9.60 nC, where the net electric field is zero. The relevant equation used is E = kq/r², with k being 8.99 x 10^9 N m²/C². A participant attempted to find the distance 'd' from the 0.600 nC charge where the electric fields from both charges balance but calculated an unreasonable distance of 9.58 m. The correct approach involves setting the electric fields equal and solving for 'd' using the distances from each charge to the point of interest.

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Homework Statement



A. Two particles having charges of 0.600 nC and 9.60 nC are separated by a distance of 1.60 m. At what point along the line connecting the two charges is the net electric field due to the two charges equal to zero?

B. Where would the net electric field be zero if one of the charges were negative?

Homework Equations



E= kq/r^2 k= 8.99X10^9

The Attempt at a Solution


I am really lost about where to start. Using the two charges and distance of 1.6m, I calculated the electric field to be 2.03X10^-8 N/C
 
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You can imagine that in between the two particles, there's a point at which the influence of one particle exactly balances that of the other. Call the distance from this point to the 0.6 nC charge "d". Can you set up an algebraic relation that states "this charge must create the same electric field as this other charge"?
 
so, should I set the electric fields due to each charge equal to each other and solve for d?

maybe, E1= kq1/d^2, E2=kq2/d^2 and so kq1/d^2=kq2/d^2 and d=square root(kq1+kq2)

I did this, but I get d to be 9.58 m, which doesn't sound reasonable

Is there a better way of doing this?
 

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