Net Electric Field due to 2 different charges

In summary, the problem involves two particles with charges of 0.600 nC and 9.60 nC separated by a distance of 1.60 m. The net electric field due to the two charges is equal to zero at a point between them where the influence of one charge balances the other. Using the equation E= kq/r^2, where k= 8.99X10^9, an attempt at solving for the distance between the two charges resulted in an unrealistic value of 9.58 m. Alternative methods may be necessary to find the correct distance.
  • #1
Ahmad1129
2
0

Homework Statement



A. Two particles having charges of 0.600 nC and 9.60 nC are separated by a distance of 1.60 m. At what point along the line connecting the two charges is the net electric field due to the two charges equal to zero?

B. Where would the net electric field be zero if one of the charges were negative?

Homework Equations



E= kq/r^2 k= 8.99X10^9

The Attempt at a Solution


I am really lost about where to start. Using the two charges and distance of 1.6m, I calculated the electric field to be 2.03X10^-8 N/C
 
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  • #2
You can imagine that in between the two particles, there's a point at which the influence of one particle exactly balances that of the other. Call the distance from this point to the 0.6 nC charge "d". Can you set up an algebraic relation that states "this charge must create the same electric field as this other charge"?
 
  • #3
so, should I set the electric fields due to each charge equal to each other and solve for d?

maybe, E1= kq1/d^2, E2=kq2/d^2 and so kq1/d^2=kq2/d^2 and d=square root(kq1+kq2)

I did this, but I get d to be 9.58 m, which doesn't sound reasonable

Is there a better way of doing this?
 

1. What is the formula for calculating the net electric field due to 2 different charges?

The formula for calculating the net electric field due to 2 different charges is given by: E = k * (q1/r1^2 + q2/r2^2), where E is the net electric field, k is the Coulomb's constant, q1 and q2 are the magnitudes of the two charges, and r1 and r2 are the distances from the charges to the point where the electric field is being calculated.

2. How do the directions of the electric fields from 2 different charges affect the net electric field?

The directions of the electric fields from 2 different charges can either add or cancel each other out, depending on whether they are pointing in the same or opposite directions. If they are pointing in the same direction, the net electric field will be stronger, and if they are pointing in opposite directions, the net electric field will be weaker.

3. Can the net electric field be zero when 2 different charges are present?

Yes, the net electric field can be zero if the magnitudes of the two charges are equal and opposite, and they are located at the same distance from the point where the electric field is being calculated. In this case, the electric fields from the two charges will cancel each other out, resulting in a net electric field of zero.

4. How does the distance between the 2 charges affect the net electric field?

The distance between the 2 charges affects the net electric field by following the inverse square law. As the distance between the charges increases, the net electric field decreases. This means that the closer the charges are to each other, the stronger the net electric field will be.

5. What is the unit of measurement for net electric field due to 2 different charges?

The unit of measurement for net electric field due to 2 different charges is newtons per coulomb (N/C).

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