Net Electric Field: Find Magnitude @ x=6cm

[figs]

Two charges are placed on the x axis. One charge (q1=+8.45 mC) is at x1=+2.55 cm and the other (q2=-21.4 mC) is at x2=+9.01 cm. Find the magnitude of the net electric field at x=6 cm.

I used this equation:
(x is in cm)

(N/C) = {(k * 8.45*10^-6) / [(x+2.55)^2 / 100]} - {(k * 21.4*10^-6) / [(x-9.01)^2 / 100]}

and my solution is not correct.

 

[dextercioby]

Did u add the 2 vectors correctly??Post the first part of your calculations.It's essential.

Daniel.

 

[figs]

figured it out, thx.
i just needed to change
some signs in that equation.

 

[dextercioby]

Well,u see,that's why it was important to check your initial setting...Some or maybe one sign wrong can make a whole lot of difference,and with vectors u always have to keep an eye out...

Daniel.