- #1

PHYSteve

- 2

- 0

did as best I could to complete it similarly. However, when I attempt to input my final

answer I get it wrong every time. I just wanted to see where I am going wrong, thanks.

## Homework Statement

Coulomb's law for the magnitude of the force F between two particles with charges

Q and Q' separated by a distance d is:

|F| = K(|QQ'|)/d

^{2}

Consider two point charges located on the x axis:

one charge, q

_{1}= -14.5nC, is located at x

_{1}= -1.745m

the second charge, q

_{2}= 36.5nC, is located at the origin.

What is the net force exerted by these two charges on a third charge

q

_{3}= 45.5nC, placed between q

_{1}and q

_{2}at x

_{3}= -1.085?

Your answer may be positive or negative, depending on the direction of the force

## Homework Equations

K = 1/4[itex]\pi[/itex][itex]\epsilon[/itex]

_{0}

## The Attempt at a Solution

I found the distance between q

_{1}and q

_{1}to be 0.660m

I found the distance between q

_{3}and q

_{2}to be 1.085m

I began by finding the charge q

_{1}exerts on q

_{3}

by:

|F

_{1}| = K*[|(-14.5*45.5)|/(0.660

^{2})] = 1.362E

^{13}

(At this point in the problem there is a hint section asking for this force, when I submit the answer I calculated I am told it is wrong.)

And then I found the charge q

_{2}exerts on q

_{3}by:

|F

_{2}| = K*[|(45.5*36.5)|/(1.085

^{2})] = 1.268E

^{13}

(Again, there is a hint section asking for this value, which also tells me it is wrong)

From those two calculated forces I take F1 - F2 to get a final answer, which is ultimately deemed incorrect.

Any help would be appreciated!