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Net force given 40 degree angle, coef. of kinetic friction=.3, and mass=80kg

  1. Oct 16, 2007 #1
    1. The problem statement, all variables and given/known data

    angle is in relation to horizontal

    2. Relevant equations
    f net=m*a


    3. The attempt at a solution

    yikes! i don't know!

    i appreciate ANY help!
     
  2. jcsd
  3. Oct 16, 2007 #2

    Astronuc

    User Avatar

    Staff: Mentor

    Please write one's work and show an attempted solution. Is the angle above or below the horizontal - it makes a difference.

    Please refer to - http://hyperphysics.phy-astr.gsu.edu/hbase/N2st.html#c2 - for some ideas.

    A mass m has weight W = mg, and that weight (which is normal to the horizontal) will have a friction force f = [itex]\mu[/itex]mg, where [itex]\mu[/itex] = coefficient of friction.

    Now the external (applied) force at a angle can be resolved into horizontal and vertical forces.

    When the horizontal applied force exceeds friction, the net force (Fnet causes the mass m to accelerate a.
     
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