Net force given 40 degree angle, coef. of kinetic friction=.3, and mass=80kg

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SUMMARY

The discussion focuses on calculating the net force acting on an 80 kg mass at a 40-degree angle with a coefficient of kinetic friction of 0.3. The weight of the mass is determined using the formula W = mg, where g is the acceleration due to gravity. The applied force at an angle is resolved into horizontal and vertical components, and the net force is calculated by subtracting the frictional force from the horizontal applied force. The frictional force is calculated as f = μmg, where μ is the coefficient of friction.

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  • Understanding of Newton's laws of motion
  • Knowledge of vector resolution of forces
  • Familiarity with the concept of friction and its coefficient
  • Basic algebra for solving equations
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This discussion is beneficial for physics students, educators, and anyone looking to understand the dynamics of forces acting on objects, particularly in scenarios involving angles and friction.

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Homework Statement



angle is in relation to horizontal

Homework Equations


f net=m*a


The Attempt at a Solution



yikes! i don't know!

i appreciate ANY help!
 
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Please write one's work and show an attempted solution. Is the angle above or below the horizontal - it makes a difference.

Please refer to - http://hyperphysics.phy-astr.gsu.edu/hbase/N2st.html#c2 - for some ideas.

A mass m has weight W = mg, and that weight (which is normal to the horizontal) will have a friction force f = [itex]\mu[/itex]mg, where [itex]\mu[/itex] = coefficient of friction.

Now the external (applied) force at a angle can be resolved into horizontal and vertical forces.

When the horizontal applied force exceeds friction, the net force (Fnet causes the mass m to accelerate a.
 

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