Net Force of A: Diagram Analysis

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SUMMARY

The discussion focuses on calculating the net force acting on object A using vector analysis. Participants emphasize the importance of determining the individual forces, specifically FAB and FAC, and applying the relevant equations: FAB = KqAqB/r2, Fx = Fcosθ, and Fy = Fsinθ. The net force is then computed using the formula FR = √(Fx2 + Fy2) and the angle θ = tan-1(Fy/Fx).

PREREQUISITES
  • Understanding of vector forces and their components
  • Familiarity with Coulomb's Law (KqAqB/r2)
  • Basic trigonometry for resolving forces into components
  • Ability to perform calculations involving square roots and inverse tangents
NEXT STEPS
  • Study vector addition of forces in physics
  • Learn about Coulomb's Law and its applications in electrostatics
  • Explore trigonometric functions in the context of physics problems
  • Practice problems involving net force calculations in two dimensions
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and forces, as well as educators looking to enhance their teaching of vector analysis and force calculations.

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Homework Statement
Find the net force of A as shown in the diagram.
Relevant Equations
FAB=KqAqB/r2
Fx=Fcosθ
Fy=Fsinθ
FR=square root of the total of Fx^2+the total of Fy^2
θ=tan-1(Fy/Fx)
Find the net force of A as shown in the diagram.
 

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:welcome:

Well, what is your question?

## \ ##
 
I think you want to find Fnet A ...

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1646687015945.png

1646687513387.png

Tell me which part you need explanation.
 
Spotify said:
Homework Statement:: Find the net force of A as shown in the diagram.
Relevant Equations:: FAB=KqAqB/r2
Fx=Fcosθ
Fy=Fsinθ
FR=square root of the total of Fx^2+the total of Fy^2
θ=tan-1(Fy/Fx)

Find the net force of A as shown in the diagram.
You need to find the vector forces ## F_{AB} ## and ## F_{AC} ## and sum those force vectors to get the total force on A. Can you show us your work on that?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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