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Net Force of A: Diagram Analysis
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To find the net force on object A, the relevant equations include the force between charges FAB=KqAqB/r², and the components of the forces Fx=Fcosθ and Fy=Fsinθ. The total force can be calculated using the formula FR=sqrt(Fx² + Fy²) and determining the angle θ with θ=tan⁻¹(Fy/Fx). Participants are encouraged to calculate the vector forces F_AB and F_AC, then sum these vectors to obtain the total force acting on A. Providing the calculations will help clarify the process.
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BvU
Science Advisor
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Well, what is your question?
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- #3
MatinSAR
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I think you want to find Fnet A ...
Tell me which part you need explanation.
Tell me which part you need explanation.
- #4
berkeman
Admin
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You need to find the vector forces ## F_{AB} ## and ## F_{AC} ## and sum those force vectors to get the total force on A. Can you show us your work on that?Spotify said:
My attempt:
Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE.
PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##.
PE of part in the tube = ##\frac{m}{l}(l - h)gh##.
Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##.
Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...
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