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Homework Statement
A long, straight wire carries a current of I1 = 15.8 A. Next to the wire is a square loop with sides L = 1.17 m in length. d = 1.42 m, as shown in the figure below.
The loop carries a current of I2 = 2.66 A in a direction parallel to the wire. Calculate the magnitude of the net force acting on the loop.
Homework Equations
The equation i have used is Force = I2*L*[(μ0*I1)/(2*pi*d)]
The Attempt at a Solution
Because i am looking for force of the loop, here are my numbers plugged in:
Force = 2.66*1.17*[(μ0*15.8A)/(2*3.14*1.42m)]
= 6.93*10^-6N, answer is incorrect
I am stumped.. any help would be greatly appreciated, thanks!