Net torque question? Block 1 and block 2 hanging on pulley?

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SUMMARY

The discussion centers on calculating the rotational inertia of a pulley system involving two blocks with masses m1=460g and m2=500g, as depicted in Fig. 10.45. The pulley has a radius of R=5.0cm and operates with negligible friction. The net torque is determined using the equation Ʃτ = (T2 - T1) R, where only the tensions in the strings are considered, not the gravitational forces acting on the masses. This approach emphasizes the importance of analyzing the system from the perspective of the pulley, which only responds to the tensions exerted by the strings.

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In Fig. 10.45, block 1 has mass m1=460g, block 2 has mass m2=500g, and the
pulley, which is mounted on a horizontal axle with negligible friction ahs radius
R=5.0cm. When released from rest, block 2 falls 75.0cm in 5.00 s without the
cord slipping on the pulley.

(e) What is its rotational inertia?

problem and picture on page 2 problem #55

http://faculty.kfupm.edu.sa/PHYS/marzoug/Phys101/chapter 10 problmes.pdf




Ʃτ = (T2 - T1) R

Why doesn't mg1 or mg2 get calculated into the net torque and only the tensions?



thanks!
 
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Why doesn't mg1 or mg2 get calculated into the net torque and only the tensions?
That happens later - there are three free-body diagrams.
It's good discipline for more complicated problems: the pulley knows nothing about the masses - all it feels is these strings pulling on it.
Note - the 1 and the 2 belong on the "m"'s not the "g"'s ... g is a constant.
 
Simon Bridge said:
That happens later - there are three free-body diagrams.
It's good discipline for more complicated problems: the pulley knows nothing about the masses - all it feels is these strings pulling on it.
Note - the 1 and the 2 belong on the "m"'s not the "g"'s ... g is a constant.

thanks!
 

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