Find the net torque on the pulley

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SUMMARY

The net torque on the pulley is calculated using the tensions in the ropes on either side of the pulley. Given a radius of 13.0 cm and a moment of inertia of 0.230 kg m², the correct formula for net torque (τ) is τ = (T_larger - T_smaller) * r. With tensions of 35.2 N and 21.6 N, the net torque is computed as τ = (35.2 N - 21.6 N) * 0.13 m, resulting in a net torque of 1.77 Nm. The initial miscalculation arose from using the height instead of the radius in the torque equation.

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Homework Statement



The pulley in the figure has radius 13.0 cm and a moment of inertia 0.230 kg m^2; the pulley is constructed from a dense metal. The rope does not slip on the pulley rim. The system is released from rest.

http://session.masteringphysics.com/problemAsset/1000057320/10/YF-09-36.jpg

Find the net torque on the pulley, about its axle, due to the differing tensions in the rope on the two sides of the pulley.

Homework Equations





The Attempt at a Solution



From earlier parts of the problem i have found the acceleration of the blocks a = 1.0m/s^2 and the velocity final of the larger falling block v = 3.16 m/s. i also found the tension in both of the ropes. T in rope attached to the larger mass was 35.2 N and the T in the rope on the smaller mass was 21.6 N

Now i cannot find the net torque it is asking for

I tried doing this

t = torque

tlarger block - tsmaller block = tnet

T*d - T*d = tnet

35.2N(5m) - 21.6N(5m) = tnet

tnet = 68Nm

This is wrong? How else can i go about this problem?

thank you
 
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i was using the height instead of the radius

i got it now :)
 

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