- #1
chiggs24
- 3
- 0
Hi All,
New to the forum, but requiring a certain amount of assistance if possible.
In relation to ice defrost time, 334 Joules per gram is required to change the state of ice to water and 2.03 joules per gram is required to raise the temperature of ice by one degree?
With this in mind, is it safe to calculate, that hypothetically, if you have around 2kg of ice and the ambient temperature is minus 5degreesC, in order to melt the ice, you require 20,300J to raise the temperature to 0, then 668,000J to complete the phase change to water, which equates to a total of 0.191194kWh?
If a 50litre vessel of water held at 50 degrees C indoors (20 degree room temperature) contains 1.75kWh, can you then calculate that the vessel will give up 0.20416kW in 7 minutes, enough to melt the 2 kilos of ice?
Im not a physicist, so if any of the above calculations have been wildly misunderstood, please do not hesitate to correct me :)
Thank you all in advance
New to the forum, but requiring a certain amount of assistance if possible.
In relation to ice defrost time, 334 Joules per gram is required to change the state of ice to water and 2.03 joules per gram is required to raise the temperature of ice by one degree?
With this in mind, is it safe to calculate, that hypothetically, if you have around 2kg of ice and the ambient temperature is minus 5degreesC, in order to melt the ice, you require 20,300J to raise the temperature to 0, then 668,000J to complete the phase change to water, which equates to a total of 0.191194kWh?
If a 50litre vessel of water held at 50 degrees C indoors (20 degree room temperature) contains 1.75kWh, can you then calculate that the vessel will give up 0.20416kW in 7 minutes, enough to melt the 2 kilos of ice?
Im not a physicist, so if any of the above calculations have been wildly misunderstood, please do not hesitate to correct me :)
Thank you all in advance