New to the forums, trouble with an integral

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Homework Help Overview

The original poster is seeking assistance with an indefinite integral involving trigonometric functions, specifically the integral of (Sin(2x))/(Sinx)dx. The context is centered around integral calculus and the application of trigonometric identities.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of trigonometric identities, particularly the identity sin(2x) = 2sin(x)cos(x), as a potential approach to simplify the integral. The original poster inquires about the possibility of using substitution.

Discussion Status

Some participants have confirmed the use of the trigonometric identity as a correct approach, while the original poster expresses a sense of being new to the topic and acknowledges the need to learn more about these identities. There is an indication of helpful guidance being provided, but no explicit consensus on the next steps has been reached.

Contextual Notes

The original poster identifies themselves as new to the forums and expresses uncertainty about their understanding of the topic, suggesting a potential gap in foundational knowledge regarding trigonometric identities.

jhayes25
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Hello all, I am new to these forums. I'm having trouble with a problem on homework. It seems simple but it is giving me problems.

It is an indefinite integral: Integral of (Sin(2x))/(Sinx)dx

Is there a way to use substitution? Help is appreciated.
 
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\int\frac{\sin{2x}}{\sin x}dx

Use the trig identity.

\sin{2x}=2\sin x \cos x
 
Use the identity:

sin(2x) = 2sin(x)cos(x)
 
roco, that is correct. Obviously a newb, I have no idea how you did that. I'm sure there are stickies somewhere that I need to read.
 
Alright, wow that is simple when you now the identities. Guess i should get to learning those lol thanks awvvu
 

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