Let f(x)=x^2 - a, where a>0. The roots of the equation f(x)=0 are +root(a), -root(a).(adsbygoogle = window.adsbygoogle || []).push({});

Show that if x1 > 0 is any initial estimate for root(a), then the Newton-Raphson method gives the iteration formula

x n-1 = 1/2( xn + a/xn ),

n>=1

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# Newton-Raphson question

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