Newton's 2nd Law: Why is Resistance Considered a Positive Force?

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Homework Help Overview

The discussion revolves around the application of Newton's second law of motion in the context of resistance forces, specifically questioning why resistance is considered a positive force in a given exercise despite being described as a negative force due to its direction opposing motion.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are exploring the interpretation of resistance as a positive force in the context of Newton's second law, questioning the definitions and assumptions made in the exercise. There is a focus on understanding the net force and the implications of describing forces as positive or negative.

Discussion Status

The conversation is ongoing, with participants seeking clarity on the terminology used in the exercise and the rationale behind considering resistance as a positive force. Some guidance has been offered regarding the need for clarity in describing forces, but no consensus has been reached on the interpretation of the exercise.

Contextual Notes

Participants note that the exercise is from a physics textbook, and there is a concern regarding the representation of forces as vectors with both magnitude and direction. There is also a mention of the need for clearer numerical representation in discussions.

Fakhro
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Homework Statement
An airboat with mass 3.50 3 102 kg, including the passenger,
has an engine that produces a net horizontal force of 7.70 3 102 N,
after accounting for forces of resistance (see Fig. 4.7). (a) Find the acceleration
of the airboat. (b) Starting from rest, how long does it take the
airboat to reach a speed of 12.0 m/s? (c) After reaching that speed, the
pilot turns off the engine and drifts to a stop over a distance of 50.0 m.
Find the resistance force, assuming it’s constant.
Relevant Equations
Newton's 2nd law of motion
regarding the last question.

I know that resistance is a negative force because it goes in the opposite direction to the movement of the boat. So whenever, I want to apply Newton's 2nd law of motion: the sum of forces = m a
I should write - F resit = m.a.
However, they have considered the resistance a positive force in this exercise. Why?
 
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Fakhro said:
I should write - F resit = m.a
Are you talking about part (a) or part (c)? If it's part (a), Newton's second law says that the net force is equal to mass times acceleration, not just the resistive force. What is the net force in part (a)?
Fakhro said:
However, they have considered the resistance a positive force in this exercise. Why?
Please tell us who "they" are and exactly what "they" said. I agree that the resistive force is opposite to the motion.
 
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kuruman said:
Are you talking about part (a) or part (c)? If it's part (a), Newton's second law says that the net force is equal to mass times acceleration, not just the resistive force. What is the net force in part (a)?

Please tell us who "they" are and exactly what "they" said. I agree that the resistive force is opposite to the motion.
Sir, when I say the last question I mean C.
the problem is not of who are. "they".
the problem lies in the exercise. In the end, the resistance force was listed as a positive force when Newton's second law was applied. the sum of forces = m a / F resit = m.a.
whereas it should be written as - F resit = m.a.

This exercise is from a physics book. They mean the authors.
 
As I already said, you are right in saying that the resistive is opposite to the motion. If you have a number for the resistive force, say 50 N, then a correctly phrased answer would be "the resistive force is 50 N in a direction opposite to the velocity." That says it all. If the textbook gives you just a positive number as the answer, then it is incorrect because force is a vector that has magntude and direction.

For future reference, please post numbers, especially powers of 10, sing LaTeX. If you have not used LaTeX before, click in the link "LaTeX Guide", lower left. Numbers such as 3.50 3 102 kg are hard to interpret. Thank you.
 
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