Newton's 2nd Law: Why is Resistance Considered a Positive Force?

AI Thread Summary
Resistance is typically considered a negative force because it opposes the direction of motion, which aligns with Newton's second law stating that the sum of forces equals mass times acceleration. In the discussed exercise, resistance was incorrectly labeled as a positive force, leading to confusion. The correct representation should reflect that the resistive force is negative, indicating its opposite direction to motion. Clarity in physics problems is essential, particularly in specifying both magnitude and direction of forces. Proper notation, such as using LaTeX for numbers, is also encouraged for better understanding.
Fakhro
Messages
2
Reaction score
0
Homework Statement
An airboat with mass 3.50 3 102 kg, including the passenger,
has an engine that produces a net horizontal force of 7.70 3 102 N,
after accounting for forces of resistance (see Fig. 4.7). (a) Find the acceleration
of the airboat. (b) Starting from rest, how long does it take the
airboat to reach a speed of 12.0 m/s? (c) After reaching that speed, the
pilot turns off the engine and drifts to a stop over a distance of 50.0 m.
Find the resistance force, assuming it’s constant.
Relevant Equations
Newton's 2nd law of motion
regarding the last question.

I know that resistance is a negative force because it goes in the opposite direction to the movement of the boat. So whenever, I want to apply Newton's 2nd law of motion: the sum of forces = m a
I should write - F resit = m.a.
However, they have considered the resistance a positive force in this exercise. Why?
 
Physics news on Phys.org
Fakhro said:
I should write - F resit = m.a
Are you talking about part (a) or part (c)? If it's part (a), Newton's second law says that the net force is equal to mass times acceleration, not just the resistive force. What is the net force in part (a)?
Fakhro said:
However, they have considered the resistance a positive force in this exercise. Why?
Please tell us who "they" are and exactly what "they" said. I agree that the resistive force is opposite to the motion.
 
kuruman said:
Are you talking about part (a) or part (c)? If it's part (a), Newton's second law says that the net force is equal to mass times acceleration, not just the resistive force. What is the net force in part (a)?

Please tell us who "they" are and exactly what "they" said. I agree that the resistive force is opposite to the motion.
Sir, when I say the last question I mean C.
the problem is not of who are. "they".
the problem lies in the exercise. In the end, the resistance force was listed as a positive force when Newton's second law was applied. the sum of forces = m a / F resit = m.a.
whereas it should be written as - F resit = m.a.

This exercise is from a physics book. They mean the authors.
 
As I already said, you are right in saying that the resistive is opposite to the motion. If you have a number for the resistive force, say 50 N, then a correctly phrased answer would be "the resistive force is 50 N in a direction opposite to the velocity." That says it all. If the textbook gives you just a positive number as the answer, then it is incorrect because force is a vector that has magntude and direction.

For future reference, please post numbers, especially powers of 10, sing LaTeX. If you have not used LaTeX before, click in the link "LaTeX Guide", lower left. Numbers such as 3.50 3 102 kg are hard to interpret. Thank you.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top