Newton's Law of Cooling problem

Click For Summary
SUMMARY

The discussion focuses on formulating a differential equation based on Newton's Law of Cooling, specifically for a cup of coffee cooling in a room at 20°C. The temperature T of the coffee is defined as a function of time t, with the cooling rate being proportional to the temperature difference between the coffee and the room temperature. The equation derived is dT/dt = -C(T - 20), where C is a positive proportionality constant. The solution involves integrating the equation using natural logarithms and exponential functions.

PREREQUISITES
  • Understanding of differential equations
  • Familiarity with Newton's Law of Cooling
  • Knowledge of integration techniques
  • Basic concepts of temperature and heat transfer
NEXT STEPS
  • Study the derivation of Newton's Law of Cooling in detail
  • Learn how to solve first-order linear differential equations
  • Explore applications of exponential decay in real-world scenarios
  • Investigate the use of initial conditions in solving differential equations
USEFUL FOR

Students in physics or mathematics, educators teaching differential equations, and anyone interested in the practical applications of Newton's Law of Cooling in thermal dynamics.

jackleyt
Messages
20
Reaction score
0

Homework Statement


The temperature T of a cup of coffee is a function T(t) where t is the time in minutes. The room temperature is 20 ^\circ Celsius. The rate at which the coffee cools down is proportional to the difference between the temperature of the coffee and the room temperature. Use this information to write a differential equation describing the derivative of the coffee temperature in terms of T and t. Use C as your proportionality constant. C should be a positive number. Write T instead of T(t).


Homework Equations





The Attempt at a Solution


I don't know where to start.
 
Physics news on Phys.org


I'm pretty sure this is Newton's Law of Cooling. The problem states that the change in temperature(derivative) is proportional(C) to the difference between the two temps(TempCoffee-20).

So the equation would look like Change in Temp=(Proportional Constant)X(Difference in temperature).

From there, you get your DT and T to the same side and integrate. The solution involves ln and e. Good luck!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
11K
  • · Replies 3 ·
Replies
3
Views
15K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
14
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K