Newton's second law and ice skating

[jehan4141]

Hello no answer is given to this problem so could somebody please tell me if the answer is correct?

thanks so much!

Two ice skaters, Paul and Tom, are each holding on to opposite ends of the same rope. Each pulls the other toward him. The magnitude of Paul's acceleration is 1.25 times greater than the magnitude of Tom's acceleration. What is the ratio of Paul's mass to Tom's mass?

Answer: They both experience the same amount of force, F=ma. However Paul's acceleration is 1.25 greater than Tom's acceleration. Acceleration and mass are inversely related. Thus, Tom's mass must be 1.25 times greater than Paul's mass. Thus P:T is 1:1.25 or 0.8

 

[Dr. 104]

Yes that looks correct to me.