Nichrome Resistor and Copper wire

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SUMMARY

The discussion centers on calculating the temperature change required for a Nichrome resistor to match the resistance of copper leads in an electronic circuit. The Nichrome resistor has a resistance of 10 ohms, while the copper leads introduce an additional resistance of 0.03 ohms. The coefficients of linear expansion for copper and Nichrome at 20 degrees Celsius are 3.9 x 10^-3 and 4.3 x 10^-3, respectively. The initial attempt yielded a temperature of 30.6°C, which was incorrect, indicating a need for further algebraic verification.

PREREQUISITES
  • Understanding of electrical resistance and its temperature dependence
  • Familiarity with the coefficients of linear expansion for materials
  • Basic algebra skills for solving equations
  • Knowledge of Nichrome and copper properties in electronic circuits
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  • Review the principles of thermal expansion in conductors
  • Study the effects of temperature on resistance in materials
  • Practice solving equations involving multiple variables
  • Explore the applications of Nichrome resistors in electronic circuits
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Homework Statement


A 10 ohms Nichrome resistor is wired into an electronic circuit using copper leads (wires) of diameter 0.6 mm with a total length of 50 cm. The additional resistance is due to the copper leads is 0.03 ohms.

What change in temperature would produce a change in resistance of the Nichrome-wire equal to the resistance of the copper leads?

Homework Equations



RCu = 0.03[1 + aCu(tC – 20)]= change in Rw = 10aw(tC – 20); solve for tC
aCu at 20 degree C= 3.9 x 10^-3
aw at 20 degree C = 4.3 x 10^-3

The Attempt at a Solution



0.03[1 + aCu(tC – 20)] = 10aw(tC – 20)
I solved for tc and got 30.6 C but it is not the right answer so please help.
 
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30.6 C does not solve the last equation you wrote. There must have been some algebra error made after that.

You are on the right track, try again. You can check your answer by substituting it into your equation,
0.03[1 + aCu(tC – 20)] = 10aw(tC – 20)
 

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