No-communication theorem question

Hey all,

Performing observations on 1 of 2 entangled particles does not allow instantaneous transmission of information between them. But since the entangled particles compromise a single quantum system, why can't we interact with one particle to influence the other?

Example: Bob and Alice each have one of two spin entangled particles, which are in isolating boxes, and are still coherent. They are very far away. Before "observing" his particle, Bob applies a magnetic field across his box, in the up direction. Since he is changing the quantum state of his particle, Alice's particle must change as well, since they are a single system, right?

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DrChinese
Gold Member
Example: Bob and Alice each have one of two spin entangled particles. They are very far away. Before "observing" his particle, Bob applies a magnetic field to his particle. Since he is changing the quantum state of his particle, Alice's particle must change as well, since they are a single system, right?

If you change the state by doing something that "reveals" an observable's value, then the entangled partner particle will change accordingly. But you will simply have it jump into a random eigenstate. That is why no communication is possible. (If you act on the particle in such a way as to not cause a wave function collapse, then the other particle does not experience that. Example is changing its direction of travel.)

If you change the state by doing something that "reveals" an observable's value, then the entangled partner particle will change accordingly. But you will simply have it jump into a random eigenstate. That is why no communication is possible. (If you act on the particle in such a way as to not cause a wave function collapse, then the other particle does not experience that. Example is changing its direction of travel.)

Thks DrChinese - So suppose after applying this magnetic field, Bob opens his box and observes his particle. Since the magnetic field is up, the particle will surely collapse to the "up" eigenstate? And if so, (assuming that the entangled particles were created from a no initial net spin system), Alice's must collapse to the "Down" eigenstate to ensure conservation of spin?

DrChinese
Gold Member
Thks DrChinese - So suppose after applying this magnetic field, Bob opens his box and observes his particle. Since the magnetic field is up, the particle will surely collapse to the "up" eigenstate? And if so, (assuming that the entangled particles were created from a no initial net spin system), Alice's must collapse to the "Down" eigenstate to ensure conservation of spin?

The field is oriented in a direction so that the result can be UP or DOWN for Alice. And you would then see DOWN or UP for Bob accordingly. You can orient in any direction to get the UP/DOWN random results.

The field is oriented in a direction so that the result can be UP or DOWN for Alice. And you would then see DOWN or UP for Bob accordingly. You can orient in any direction to get the UP/DOWN random results.

I'm not sure I understand - the magnetic field is aligned on the same axis that bob and alice are making their observations. You would most likely never see a "down" observation for Bob, or a corresponding "up" observation for alice, since his particle will be influenced by the magnetic field, right?

I guess what I'm asking is: If I introduce an external potential to 1 of 2 entangled particles such that it changes the quantum state of that particle without decohere-ing the entangled system, do the particles remain entangled when they finally do decohere?

DrChinese