1. Apr 24, 2009 #1

   chhitiz

   

   can somebody please tell me if there is any way to find all values of k for which 6k²+4k is of form 6ab+5a+b? eg. for k=1, 6k²+4k=10=6x0x2+5x2+0

    

   chhitiz, Apr 24, 2009
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3. Apr 27, 2009 #2

   Almutairi

   

   I might have misunderstood the question, but Based on what you made a=2 and b=0. Can you give them any value you want?
   In that case can't you always make a=0, b= (6K ² +4k)?
   So that 6k²+4k is always of the form 6ab+5a+b, where K is any rational number.
   eg. for k=1, 6k²+4k=10=6x0x10+5x0+10
   Or should I just go back to my lunch

    

   Almutairi, Apr 27, 2009
4. Apr 27, 2009 #3

   chhitiz

   

   yeah sorry about that, but a can't be 0. has to be a integer>0. b,though can be >=0

    

   chhitiz, Apr 27, 2009

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