No one has figured this out Problem I'm stuck

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The problem involves a 2.0 kg block on a compressed spring, released to rise 0.60 m with a velocity of 1.7 m/s. To find the potential energy in the spring, the conservation of energy principle is applied, combining kinetic energy (KE) and potential energy (PE) equations. The initial potential energy in the spring can be expressed as PE = 0.5kx^2, where x is the compression of the spring. The energy balance equation is set up as E = 0.5mv^2 + 0.5kx^2. This approach leads to determining the spring's potential energy before the block was released.
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a block of mass 2.0 kg is placed on a compressed vertical spring that is compressed .050m. (The spring and the block are not attached) The spring is released, and it propels the block vertically upward. when the block has risen .60m abovie its initial position, its velocity is 1.7 m/s. how much potential energy was originally in the spring?
 
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Set up an energy balance equation. Then go from there.
 
First hint look into conservation of energy.

Here are some formulas to look into

PE=.5kx^2

k=spring constant
x=position

KE=.5mv^2

Combine them to form conservation of energy

E=.5mv^2+.5kx^2
 

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