Non-uniform circular motion question

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An object with a mass of 0.500 kg is suspended in an accelerating truck with an acceleration of 3.00 m/s², prompting a calculation of the angle θ the string makes with the vertical and the tension T in the string. The initial attempt incorrectly assumed mg is greater than T, leading to confusion in resolving forces. The correct approach recognizes that the tension must counteract both the gravitational force and the truck's acceleration. A diagram is recommended to visualize the forces acting on the mass, which include the weight (mg) and the tension (T). Understanding the balance of these forces is crucial for solving the problem accurately.
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Homework Statement


An object of mass m=.500kg is suspended from the ceiling of an accelerating truck. Taking a=3.00m/s^2 find the angle θ that the string makes with the vertical and the tension T in the string.


Homework Equations





The Attempt at a Solution


mgsinθ=ma => sinθ=1.5/4.9 =>θ=17.8

mgcosθ=T => T=4.67N

But alas this is incorrect. Where did I fail?
 
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Be careful with mg & T.

For example, in your second equation, you're implying that mg is bigger than T, think about why that can't be true.

Your resolving is fine though, just think about the mg & T, if you need more help just ask.

Edit: I'm also not sure what this has to do with circular motion.
 
As to why circular motion...got me. It's in that chapter in the book.

With T and mg, wouldn't mg be bigger since due to acceleration? If I reverse my equation and have T bigger, is it mg-Tcosθ? and why?
 
The reverse is correct. Draw yourself a diagram and label all of the forces.

The string has to both support the weight of the mass (mg) in the upward direction, but it also acts against the acceleration of the lorry which pushes the mass towards the back of the lorry. Because the net force on it is 0, right? Anyway, I think the diagram should help.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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