Nonlinear differential equation problem.

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SUMMARY

The discussion focuses on solving the nonlinear differential equation given by y′(x)² + 1 = y′′(x) y(x). The solution involves applying the identity y'' = y' (dy'/dy) to transform the equation into a more manageable form. By rearranging the terms, the equation can be expressed as (y' dy')/(1+y'²) = dy/y, allowing for integration on both sides. This method leads to a solution for y' in terms of y, which can then be integrated a second time to find y.

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Homework Statement


The following equation turned up while I was trying to make an integral
stationary in a 'calculus of variations' problem.

[tex]y^{\prime}(x)^2 + 1 = y^{\prime\prime}(x) y(x)[/tex]

How would one go about solving this nonlinear equation?
 
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Equations like this, which do not contain the independent variable (x), can be solved by applying the identity:
[tex]y'' = \frac{d^2y}{dx^2} = \frac{dy'}{dx} = \frac{dy'}{dy}\frac{dy}{dx} = y' \frac{dy'}{dy}[/tex]
Then you can write:
[tex]y'^2+1 = y' \frac{dy'}{dy} y[/tex]
Then you collect terms in y and y' to get to a form you can integrate:
[tex]\frac{y' dy'}{1+y'^2} = \frac{dy}{y}[/tex]
Then integrate both sides and solve for y' in terms of y, and then integrate a second time.
 

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