Normal derivative in spheroidal coordinate

AI Thread Summary
The discussion focuses on calculating the normal derivative to the surface of an oblate spheroid using spheroidal coordinates. The relationship between spheroidal and Cartesian coordinates is provided, detailing the transformations for x, y, and z. To find the normal derivative, it is suggested to calculate a basis for the tangent space and then take the cross product. This method will yield the necessary derivatives in terms of u, v, and φ. The approach emphasizes the mathematical relationships inherent in spheroidal coordinates.
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Hi PhysicsForums,
I am calculating something related to the spheroidal membrane and want to ask you a question.

I consider a oblate spheroid (Oblate spheroidal coordinates can also be considered as a limiting case of ellipsoidal coordinates in which the two largest semi-axes are equal in length.)

In spheroidal coordinate, the relationship to Cartesian coordinates is
x=a\sqrt((1+u^2) (1-v^2))\cos(\phi)
y=a\sqrt((1+u^2) (1-v^2))\sin(\phi)
z=a u v

Now, I want to know how to achieve the normal derivative to the surface of a spheroid, in terms of the derivatives of u, v and \phi.

Thank you very much.
 
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Just calculate a basis of the tangent space and take the cross product.
 
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