Normal derivative in spheroidal coordinate

In summary, the conversation discusses calculating the normal derivative to the surface of an oblate spheroid using spheroidal coordinates. The relationship to Cartesian coordinates is given, and the method of calculating the normal derivative is explained as taking the cross product of a basis of the tangent space.
  • #1
dexturelab
5
0
Hi PhysicsForums,
I am calculating something related to the spheroidal membrane and want to ask you a question.

I consider a oblate spheroid (Oblate spheroidal coordinates can also be considered as a limiting case of ellipsoidal coordinates in which the two largest semi-axes are equal in length.)

In spheroidal coordinate, the relationship to Cartesian coordinates is
[tex]x=a\sqrt((1+u^2) (1-v^2))\cos(\phi)[/tex]
[tex]y=a\sqrt((1+u^2) (1-v^2))\sin(\phi)[/tex]
[tex]z=a u v[/tex]

Now, I want to know how to achieve the normal derivative to the surface of a spheroid, in terms of the derivatives of u, v and [tex]\phi[/tex].

Thank you very much.
 
Mathematics news on Phys.org
  • #2
Just calculate a basis of the tangent space and take the cross product.
 

What is a normal derivative in spheroidal coordinate?

A normal derivative in spheroidal coordinate is a mathematical concept used in the study of spheroidal coordinates. It refers to the rate of change of a function in the direction perpendicular to the surface of a spheroid at a specific point.

How is a normal derivative in spheroidal coordinate calculated?

The calculation of a normal derivative in spheroidal coordinate involves taking the dot product of the gradient of the function with the unit normal vector to the spheroid at the given point.

What is the significance of the normal derivative in spheroidal coordinate?

The normal derivative in spheroidal coordinate has several applications in physics and engineering. It is used in the study of fluid dynamics, electromagnetism, and heat transfer in spheroidal geometries.

Can a normal derivative in spheroidal coordinate be negative?

Yes, a normal derivative in spheroidal coordinate can be negative. This indicates that the function is decreasing in the direction perpendicular to the surface of the spheroid at that point.

How is a normal derivative in spheroidal coordinate related to the Laplace equation?

The Laplace equation involves the second derivatives of a function. The normal derivative in spheroidal coordinate can be used to express the second derivatives in terms of the first derivatives, making it a useful tool in solving the Laplace equation in spheroidal coordinates.

Similar threads

Replies
7
Views
1K
Replies
2
Views
1K
Replies
2
Views
3K
Replies
2
Views
1K
Replies
2
Views
1K
  • General Math
Replies
4
Views
1K
Replies
6
Views
5K
  • Advanced Physics Homework Help
Replies
1
Views
2K
  • Differential Geometry
Replies
4
Views
2K
Replies
1
Views
2K
Back
Top