Normal modes of a two mass, two spring system?

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In a two-mass, two-spring system with equal masses, the equations of motion involve the spring constants and the displacements of the masses. To find the normal modes and frequencies, one must derive a fourth-order ordinary differential equation (ODE) from the coupled equations. The normal modes can be expressed as sinusoidal functions, where the masses oscillate with the same frequency. The challenge lies in substituting these expressions into the equations to solve for the parameters. Understanding the relationship between the masses and springs is crucial for determining the system's behavior.
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Homework Statement



I have a system of two masses m1 and m2 coupled by two springs with constants k1 and k2. If m1 and m2 are equal what would be the normal modes for this system?


Homework Equations



Equations of motion for the system:
\begin{align*}
m_1\ddot{x}_1 &= -k_1x_1+k_2(x_2-x_1) \\
m_2\ddot{x}_2 &= -k_2(x_2-x_1)
\end{align*}

The Attempt at a Solution



I am having some serious trouble understanding how to come come up with the normal modes and thus the normal frequencies for this problem. I understand in a three spring system and have read examples of the two spring system, but am still struggling with how they came to their solution. Am I supposed to grind these problems out into a 4th order ODE, and if so where do I go from there?
 
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A normal mode is ## x_1 = A \sin at, \ x_2 = B \sin at ##. Substitute this and determine a, A, B.
 
voko said:
A normal mode is ## x_1 = A \sin at, \ x_2 = B \sin at ##. Substitute this and determine a, A, B.
Why same frequency ?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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