# A Not getting how to simplify it

1. Mar 8, 2016

### Amineen

hi..how can i simplify this..i tried on mathematica but i am getting nothing but the same expression

\noindent$$\pmb{-e^{-x} \left(1-e^{-x}\right)^{-1+\beta } \left(1-\left(1-e^{-x}\right)^{\beta }\right)^{-1+\text{\alpha 1}+\text{\alpha 2}} \left(-1+\left(1-\left(1-e^{-x}\right)^{\beta }\right)^{\text{\alpha 3}}\right) (\text{\alpha 1}+\text{\alpha 2}) \beta +}\\ \pmb{\frac{\left(1-e^{-x}\right)^{\beta } \left(1-\left(1-e^{-x}\right)^{\beta }\right)^{-1+\text{\alpha 1}+\text{\alpha 3}} \left(\text{\alpha 1}+\text{\alpha 3}-\left(1-\left(1-e^{-x}\right)^{\beta }\right)^{\text{\alpha 2}} \text{\alpha 3}\right) \beta }{-1+e^x}}$$

(mentor note: tried to fix this but it didn't look right)

Last edited by a moderator: Mar 8, 2016
2. Mar 8, 2016

3. Mar 8, 2016

### Amineen

[-e^{-x} (1 - e^-x)^{(-1 + β)} (1 - (1 - e^-x)^\β)^{(-1 + α1 + α2)}(-1 + (1 - (1 - e^-x)^β)^
{α3}) (α1 + α2) β ]+[ ((1 - e^-x)^β (1 - (1 - e^-x)^β)^{(-1 + α1 + α3)} (α1 + α3 - (1 - (1 - e^-x)^β)^{α2 }α3) β)]/ (-1 + e^x)

4. Mar 8, 2016

### Staff: Mentor

You don't show how this expression arose, so it's possible that you made an error somewhere along the way. If that's the case, it's futile to try to simplify something that starts off incorrect.

5. Mar 8, 2016

### mathman

Proofread it. Use [itex] to make it readable. e^-x should be e^{-x}. ^\β is incorrect.

6. Mar 9, 2016

7. Mar 9, 2016