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A Not getting how to simplify it

  1. Mar 8, 2016 #1
    hi..how can i simplify this..i tried on mathematica but i am getting nothing but the same expression


    \noindent\(\pmb{-e^{-x} \left(1-e^{-x}\right)^{-1+\beta } \left(1-\left(1-e^{-x}\right)^{\beta }\right)^{-1+\text{$\alpha $1}+\text{$\alpha $2}}

    \left(-1+\left(1-\left(1-e^{-x}\right)^{\beta }\right)^{\text{$\alpha $3}}\right) (\text{$\alpha $1}+\text{$\alpha $2}) \beta +}\\

    \pmb{\frac{\left(1-e^{-x}\right)^{\beta } \left(1-\left(1-e^{-x}\right)^{\beta }\right)^{-1+\text{$\alpha $1}+\text{$\alpha $3}} \left(\text{$\alpha

    $1}+\text{$\alpha $3}-\left(1-\left(1-e^{-x}\right)^{\beta }\right)^{\text{$\alpha $2}} \text{$\alpha $3}\right) \beta }{-1+e^x}}\)

    (mentor note: tried to fix this but it didn't look right)
     
    Last edited by a moderator: Mar 8, 2016
  2. jcsd
  3. Mar 8, 2016 #2

    Mark44

    Staff: Mentor

    What you wrote is unreadable.
     
  4. Mar 8, 2016 #3
    [-e^{-x} (1 - e^-x)^{(-1 + β)} (1 - (1 - e^-x)^\β)^{(-1 + α1 + α2)}(-1 + (1 - (1 - e^-x)^β)^
    {α3}) (α1 + α2) β ]+[ ((1 - e^-x)^β (1 - (1 - e^-x)^β)^{(-1 + α1 + α3)} (α1 + α3 - (1 - (1 - e^-x)^β)^{α2 }α3) β)]/ (-1 + e^x)
     
  5. Mar 8, 2016 #4

    Mark44

    Staff: Mentor

    You don't show how this expression arose, so it's possible that you made an error somewhere along the way. If that's the case, it's futile to try to simplify something that starts off incorrect.
     
  6. Mar 8, 2016 #5

    mathman

    User Avatar
    Science Advisor
    Gold Member

    Proofread it. Use [itex] to make it readable. e^-x should be e^{-x}. ^\β is incorrect.
     
  7. Mar 9, 2016 #6
  8. Mar 9, 2016 #7

    Mark44

    Staff: Mentor

    This is onlyl a slight improvement over what you've already written. Also, the link you added is to this very same thread.
    As I already said,
    You need to show us where the expression above came from. Otherwise I'm going to close this thread.
     
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