- #1
groom03
- 27
- 0
I'm doing A2 Edexcel maths and i keep on forgetting the trig functions so can someone take a look and tell me if I've got it right.
So far:
Sin^2(x)=cos^2(x)=1
so:
sin^2(x)=1-cos^2(x)
cos^2(x)=1-sin^2(x)
this is where i get abit stuck
(sin^2(x)+cos^2(x)=1)/cos^2(x) = tan^2(x)+1=sec^2(x)
(sin^2(x)+cos^2(x)=1)/sin^2(x) = tan^2(x)+1=sec^2(x)
i'm not sure if I've got them wrong or if I'm meant to divide by sin(x) or sin^2(x)
Please help me
So far:
Sin^2(x)=cos^2(x)=1
so:
sin^2(x)=1-cos^2(x)
cos^2(x)=1-sin^2(x)
this is where i get abit stuck
(sin^2(x)+cos^2(x)=1)/cos^2(x) = tan^2(x)+1=sec^2(x)
(sin^2(x)+cos^2(x)=1)/sin^2(x) = tan^2(x)+1=sec^2(x)
i'm not sure if I've got them wrong or if I'm meant to divide by sin(x) or sin^2(x)
Please help me