Novice Problem for Final Velocity

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SUMMARY

The discussion centers on calculating the final velocity of a cart rolling down a ramp, with initial conditions of vi=0 m/s, D=1.84 m, and t=1.15 s. The average velocity (Vav) was calculated as 1.6 m/s, leading to a final velocity (vf) of 3.2 m/s using the formula 2Vav - vi = vf. The user questions the accuracy of their calculations compared to their textbook, prompting a discussion on the correct approach to finding acceleration using kinematic equations.

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1. A lab was performed where students roller an initially stationary cart down a ramp 1.84m long. It took 1.15s to roll off the end of the ramp. What is the final velocity of the cart?
vi=0m/s, D=1.84m, t=1.15s vf=?




2. Vav=d/t, Vav= (vi+vf)/2



3. Vav= 1.84m/1.15s=1.6m/s 2Vav-vi=vf, 2(1.6m/s)-0=vf, therefore vf= 3.2m/s

Sorry for wasting everyone's time with this novice problem, however, if this was firstly correct, and secondly the easiest way of finding final velocity. My textbook states a different answer and I was wondering if I made an error or if it was mistaken. Thanks.
 
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Simple:
<br /> V_{f}^2 = V_{i}^2 + 2 a \Delta x<br />
 
so to find acceleration would I need to find delta velocity and then just use a=v/t?
 

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