NRamp Force Problem: Find F and Normal Force on 87kg Crate

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SUMMARY

The discussion centers on calculating the horizontal force F required to push an 87 kg crate up a frictionless ramp at a constant speed, with an incline angle of 29°. The gravitational force acting on the crate is determined using the formula F = mg, yielding a value of 745.7 N for the perpendicular component (Fy). The parallel component (Fx) must also be calculated to find the total force F and the normal force acting on the crate. Summing the forces in both the x and y directions is essential for solving the problem.

PREREQUISITES
  • Understanding of Newton's laws of motion, particularly F = ma
  • Knowledge of trigonometric functions, specifically sine and cosine
  • Familiarity with vector components of forces
  • Basic principles of dynamics on inclined planes
NEXT STEPS
  • Calculate the parallel gravitational force component (Fx) using the formula Fx = mg sin(θ)
  • Determine the normal force (Fn) using the formula Fn = mg cos(θ)
  • Explore the concept of forces on inclined planes in physics textbooks or online resources
  • Practice similar problems involving forces on ramps to solidify understanding
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for examples of force calculations on inclined planes.

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Homework Statement


a crate of mass m = 87 kg is pushed at a constant speed up a frictionless ramp (θ = 29°) by a horizontal force F. The positive direction of an x-axis is up the ramp, and the positive direction of a y-axis is perpendicular to the ramp. (a) What is the magnitude of F? What is the magnitude of the normal force on the crate?

Homework Equations


I'm not sure I know F=ma


The Attempt at a Solution



I know gravitational force=mg cos(theta)=87(9.8)(cos(29))=745.7
 
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Actually the gravitational force is simply m*g and acts straight down. You are trying to find the two components of the gravitation force or weight in the directions of the shifted x,y coordinates. These components are usually called the perpendicular force 'Fy' and the parallel force 'Fx' (because one acts parallel to the incline and the other perpendicular).

So when you said you calculated the gravitational force you really calculated 'Fy'. Next calculate 'Fx'...

Last you need to sum forces in the x & y directions to solve for your unknowns.
 

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