Nuclear explosion size required to create a Shattered Horzion scenario

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Shattered Horizon is a game set in 2047, where an accident by the Moon Mining Corporation causes a significant portion of the moon to fracture, resulting in debris orbiting Earth. The storyline revolves around stranded International Space Agency workers and MMC miners competing for limited resources in space. A discussion on the feasibility of breaking the moon involves calculating the necessary underground nuclear explosion. It is estimated that if 5% of the moon's mass, approximately 10^21 kg, were to escape at the moon's escape velocity of 2.4 km/s, the resulting kinetic energy would be around 10^27 Joules, equating to roughly 10^12 megatons. However, this calculation carries a substantial margin of error, potentially spanning several orders of magnitude.
Cifyra
I'm not sure if any of you have heard about the game, Shattered Horizon. It's story takes place in 2047 when the Moon Mining Corporation accidentally fractured a large chunk of the moon and sent fragments and debris in orbit around Earth. International Space Agency workers and MMC miners are now stranded in space, as they fight over scarce resources to survive. How big of an underground nuclear explosion is require to "break" the moon as illustrated in the following video?

 
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Suppose 5% of the moons mass is now moving away from the moon at its escape velocity (2.4km/s according to wikipedia). That 5% has a mass of, very roughly, 10^21 kg. So the kinetic energy of that mass is of order 10^27 Joules. That is, very roughly, 10^12 megatons. The error on this calculation is probably plus/minus several orders of magnitude.
 

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