Nuclear Model - Expression for Total Energy [Modern Physics]

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SUMMARY

The discussion centers on deriving the expression for the total energy required to assemble a nucleus of atomic number Z and radius R, modeled as a uniformly charged sphere. The established formula for total energy is U = 3k * (Ze)² / 5R. Participants referenced the relationship between kinetic energy and electrical potential energy during alpha particle collisions with the nucleus, specifically .5mv² = k(2e)(Ze)/d. Additionally, the gravitational analog of potential energy for a sphere is noted as -3/5GM²/R, which aids in understanding the derivation process.

PREREQUISITES
  • Understanding of electrostatics, specifically Coulomb's law and potential energy.
  • Familiarity with the concept of uniform volume charge density.
  • Knowledge of basic mechanics, particularly kinetic energy equations.
  • Grasp of gravitational potential energy concepts and their analogs in electrostatics.
NEXT STEPS
  • Study the derivation of the total energy expression for uniformly charged spheres.
  • Explore the relationship between kinetic energy and potential energy in electrostatic systems.
  • Investigate the gravitational analogs of potential energy in different contexts.
  • Review advanced topics in nuclear physics related to binding energy and nuclear interactions.
USEFUL FOR

Students and educators in modern physics, particularly those focusing on nuclear physics, electrostatics, and energy derivations. This discussion is beneficial for anyone seeking to understand the principles behind nuclear assembly and energy calculations.

twotaileddemon
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Homework Statement



Derive an expression for the total energy required to asemble a sphere of charge corresponding to a nucleus of atomic number Z and radius R. Assume the nucleus is a sphere of uniform volume charge density \rho

Homework Equations



\rho = mass / volume = 3Am / 4*pi*R3

The Attempt at a Solution



I know the solution is U = 3k * (Ze)2 / 5R, so I need to work on deriving this.

I also know that when an alpha particle collides with the nucleus, the initial kinetic energy is equal to the electrical potential energy of the system and is given by
.5mv2 = kq1q2/r = k(2e)(Ze)/d where d = 4kZe2 / mv2

Not sure how this helps though, but it seems to be in a relevant section in the textbook. There is also info on the binding energy, but it doesn't seem applicable in this case.

Any tips on how to approach the problem, please?
 
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Have you ever learned of the gravitational analog? Wherein the gravitational potential energy of a sphere of mass M and radius R is -3/5GM^2/R?

You can apply that analog perfectly to this case.

If you haven't seen that. Consider a spherical shell (infinitessimal thickness), what is the potential energy of this shell? How would I go about adding up all these spherical shells to form a sphere?
 
Matterwave said:
Have you ever learned of the gravitational analog? Wherein the gravitational potential energy of a sphere of mass M and radius R is -3/5GM^2/R?

You can apply that analog perfectly to this case.

If you haven't seen that. Consider a spherical shell (infinitessimal thickness), what is the potential energy of this shell? How would I go about adding up all these spherical shells to form a sphere?

I think I remember learning about that in a different course, let me check my notes and I'll get back to you. Thanks for the tip!

EDIT 4/19: I was able to figure out how to derive the proof. Thank you!
 
Last edited:

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