The discussion centers on calculating the number of 70-ohm resistors that can be connected in a series circuit with a maximum power loss of 1800W and a supply voltage of 127V. The formula used is P = V² / (x * R), leading to the conclusion that only one resistor can be connected when R is confirmed to be 7 ohms, not 70 ohms. The calculation shows that x equals 1.28, indicating that the configuration exceeds the power limit with more than one resistor.
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chawki said:Homework Statement
How many resistors, R = 70 ohms can be connected in a series circuit when the maximum power loss of the circuit is 1800W. and the voltages supply is 127V
Homework Equations
Number of resistors!
The Attempt at a Solution
P = V2 / x*R
x*7=1272/1800
x=1.28
so only one resistor can be connected.
If R=7Ω , then this is correct !chawki said:Homework Statement
How many resistors, R = 70 ohms can be connected in a series circuit when the maximum power loss of the circuit is 1800W. and the voltages supply is 127V
Homework Equations
Number of resistors!
The Attempt at a Solution
P = V2 / x*R
x*7=1272/1800
x=1.28
so only one resistor can be connected.