Number of zero's of holomorphic function

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SUMMARY

The discussion centers on the properties of holomorphic functions within the open unit disc, specifically addressing the assertion that a holomorphic function \( f(z) \) that takes real values only on the real axis can have at most one zero in the open disc. The argument principle and Rouche's theorem are referenced as key tools for analyzing the number of zeros. The conclusion drawn is that due to the nature of holomorphic functions and the constraints imposed by the real axis, non-real zeros are excluded, reinforcing the claim of a maximum of one zero within the unit disc.

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Homework Statement



Let f(z) be holomorphic in the open unit disc taking real values only on the real axis.show that f has at most one zero in the open disc.

Homework Equations



Rouche's theorem,the argument principle.

The Attempt at a Solution


obviously,f does not have non-real zero's .I need help in counting the zero's by using the argument principle.
 
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hedipaldi said:

Homework Statement



Let f(z) be holomorphic in the open unit disc taking real values only on the real axis.show that f has at most one zero in the open disc.

Homework Equations



Rouche's theorem,the argument principle.

The Attempt at a Solution


obviously,f does not have non-real zero's .I need help in counting the zero's by using the argument principle.

I'm not an expert, but is argument is zero at +1 and -1 and can't be zero anyplace else as the contour winds around the boundary of the unit circle. What are the possibilities for the winding number?
 

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