Numerical value and log problem

In summary, the conversation is about finding the numerical value of u^(2a+(1/3)b-(2/5)c) using the given equations log_u (5) = a, log_u (27)=b, and log_u (32)=c. The suggested solution involves simplifying the expression by turning it into numbers and the final result is 18.75.
  • #1
physstudent1
270
1

Homework Statement


log_u (5) = a; log_u (27)=b; log_u(32)=c

what is the numerical value of u^(2a+(1/3)b-(2/5)c)

Homework Equations


The Attempt at a Solution



Can you do (u^2a * u^(b*1/3) ) / ( u^(c*-2/5))) and then do
log_u of the whole thing

from here can you make it

((u^a)^2 * (u^b)^1/3))/((u^c)^2/5)
 
Last edited:
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  • #2
Yes, but now u^a=5, right? What's u^b and u^c? You can turn it all into numbers.
 
  • #3
yeah so i turned them all into numbers and got 18.75 I wanted to make sure this was a legit way to solve this problem thanks dick.
 

What is a numerical value?

A numerical value is a specific quantity or measurement expressed in numerical form. It can be a whole number, decimal, fraction, or any other numerical representation.

What is a log problem?

A log problem is a mathematical equation involving logarithms, which are mathematical functions used to solve exponential equations. Log problems often involve finding the unknown value in an equation or solving for a variable.

How do I solve a log problem?

To solve a log problem, you can use the properties of logarithms, such as the product, quotient, and power rules. You can also use a calculator or table of logarithms to find the solution.

What is the difference between a logarithm and an exponent?

A logarithm is the power to which a base number must be raised to equal a given number, while an exponent is the number of times a base number is multiplied by itself. Essentially, logarithms and exponents are inverse operations of each other.

Why are logarithms useful in science?

Logarithms are useful in science because they allow us to express very large or small numbers in a more manageable form. They also help us solve complex equations and analyze data in a more efficient manner.

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