Numerical value and log problem

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SUMMARY

The discussion revolves around solving the expression u^(2a + (1/3)b - (2/5)c) given the logarithmic values log_u(5) = a, log_u(27) = b, and log_u(32) = c. Participants confirm that the expression can be rewritten as (u^2a * u^(b/3)) / (u^(c*2/5)), leading to the simplification of u^a, u^b, and u^c into their respective numerical values. The final calculated result is 18.75, validating the approach taken to solve the problem.

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Homework Statement


log_u (5) = a; log_u (27)=b; log_u(32)=c

what is the numerical value of u^(2a+(1/3)b-(2/5)c)

Homework Equations


The Attempt at a Solution



Can you do (u^2a * u^(b*1/3) ) / ( u^(c*-2/5))) and then do
log_u of the whole thing

from here can you make it

((u^a)^2 * (u^b)^1/3))/((u^c)^2/5)
 
Last edited:
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Yes, but now u^a=5, right? What's u^b and u^c? You can turn it all into numbers.
 
yeah so i turned them all into numbers and got 18.75 I wanted to make sure this was a legit way to solve this problem thanks dick.
 

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