Not exactly homework, but it is a problem I'm having...(adsbygoogle = window.adsbygoogle || []).push({});

Im given an ode that reads:

y"-2y'-3y = 6;

[itex]y_c = C_1 * /exp^-x + C_2 * /exp^3x[/itex]

[itex]y_p[/itex] is -2

y(0) = 3

y'(0) = 11

Now I am tasked to find what [itex]C_1[/itex] and [itex]C_2[/itex] are.

I know that y(x) = [itex]y_c + y_p[/itex]

so:

y = [itex]C_1 * /exp^-x + C_2 * /exp^3x[/itex] - 2

and

y' = [itex]-C_1 * /exp^-x + 3 * C_2 * /exp^3x[/itex]

The book defines the answers as:

[itex]C_1[/itex] = 1 and [itex]C_2[/itex] = 4

Yet when I work it out, Ive gotten [itex]C_1[/itex] = 2 and [itex]C_2[/itex] = 3.

What am I doing wrong?

NOTE: I hope I did the itex right... my computer isnt showing them...

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# Homework Help: O.D.E. Complementary and Particular Solution

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