# Homework Help: O.D.E. Complementary and Particular Solution

1. Mar 13, 2006

### kahless2005

Not exactly homework, but it is a problem I'm having...

Im given an ode that reads:
y"-2y'-3y = 6;
$y_c = C_1 * /exp^-x + C_2 * /exp^3x$
$y_p$ is -2

y(0) = 3
y'(0) = 11

Now I am tasked to find what $C_1$ and $C_2$ are.

I know that y(x) = $y_c + y_p$
so:
y = $C_1 * /exp^-x + C_2 * /exp^3x$ - 2
and
y' = $-C_1 * /exp^-x + 3 * C_2 * /exp^3x$

The book defines the answers as:
$C_1$ = 1 and $C_2$ = 4

Yet when I work it out, Ive gotten $C_1$ = 2 and $C_2$ = 3.

What am I doing wrong?

NOTE: I hope I did the itex right... my computer isnt showing them...

2. Mar 13, 2006

### kahless2005

Nevermind... I got it to work. I had a simple Aritmatic Error