Object A (in free fall) hits object B (ascending with constant velocity)

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Homework Help Overview

The discussion revolves around a physics problem involving two objects: Object A, which is in free fall, and Object B, which is ascending with a constant velocity. The participants are trying to determine the time at which the two objects meet, using equations of motion.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the equations of motion for both objects and express confusion about solving for time. There are attempts to define a coordinate system and clarify the physical setup of the problem. Some participants suggest drawing diagrams to visualize the scenario.

Discussion Status

There is ongoing exploration of the problem with various attempts to set up the equations correctly. Some participants have provided hints and guidance on using the quadratic formula and completing the square, while others express uncertainty about their results and the correctness of their calculations.

Contextual Notes

Participants mention constraints such as the initial heights of the objects and the acceleration due to gravity. There is also discussion about the direction of motion and how it affects the equations being used.

  • #31
groetschel said:
Ok, let me try this...
##h - vt - \frac 1 2 g t^2 = 0##
$$ ax^2 + bx + c = 0 $$
What's your final answer for t?
 
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  • #32
groetschel said:
???
Please try it on your own:
H = 2m
v = 5.833 m/s
g = 9.8 m/s2

Solve the equation for t...
You could always have checked this on a spreadsheet. You want to find ##t## such that:
$$5.833t + \frac 1 2 9.8 t^2 = 2$$You could start at ##t = 0.01## and go up in increments of ##0.01## until you get to ##2##:

ug
5.833​
9.8​
tut1/2 gt^2d
0.01​
0.05833​
0.00049​
0.05882​
0.02​
0.11666​
0.00196​
0.11862​
0.03​
0.17499​
0.00441​
0.1794​
0.04​
0.23332​
0.00784​
0.24116​
0.05​
0.29165​
0.01225​
0.3039​
 
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  • #34
groetschel said:
Ok, let me try this...
##h - vt - \frac 1 2 g t^2 = 0##
$$ ax^2 + bx + c = 0 $$
Put the first into the form of the second and identify what is a,b and c. Then use the formula given earlier for the quadratic in terms of a,b,c to solve for t (or x if that's easier).
 

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