A 2.50kg object is moving on a plane with coordinates x=2t2-4 and y=3t3-3.
Find the magnitude of the net force at t=2.00s
[tex]\Sigma[/tex]Fy = 0 (no movement on y axis)
[tex]\Sigma[/tex]Fx = m*a (mass x acceleration)
The Attempt at a Solution
Alright, first of all, nice to meet you all; this is my first post on the forum so by all means, if I'm doing something incorrectly, just let me know.
Conceptualize: Using the sum of the froces acting on x and the sum of the forces acting on y, I think I could find the magnitude of the net force with
1- I figured it would be easier to draw the diagram of the forces by taking (x,y) coordinates at t=0 & t=2 (in order to see the direction of the incline). This one seems to be going from the 3rd quadran to the first.
2- I can then write my [tex]\Sigma[/tex]Fx & [tex]\Sigma[/tex]Fy equations like this:
[tex]\Sigma[/tex]Fy = 0 = n - w
n = normal force
w = weight = mass x gravity(acceleration)
[tex]\Sigma[/tex]Fx = m * (F sin [tex]\theta[/tex])
This is where I get confused.
Should I include a y component for the force in my y (F cos [tex]\theta[/tex])?
And what other forces are acting on my x axis??
P.S.: I seem to be having problems with the code @ point 2-; if you see a square root in front of Fx, ignore it, it's a SIGMA... I tried refreshing the page and all but I keep getting the sqr root in the preview ô.O
Same goes for F sin theta... it's obviously not F sin sigma...