If we consider nonrelativistic QM, we will find Galilean group under the hood. Thanks to this, group theory enables us to find equations of motion directly from the symmetry principles. For example, if we take only geometric symmetries, we will get that the state space is broken into irreducible spaces characterized by momentum and angular momentum. For elementary system, angular momentum is zero so, condition that state lies in k-irreducible space (k being the momentum) is [tex]|\vec{P}||\Psi\rangle =|\vec{k}||\Psi\rangle[/tex] or [tex]P^2|\Psi\rangle=k^2|\Psi\rangle[/tex] which is Shrodinger equation for free particle [tex](\nabla^2+k^2)\Psi(\vec{r})=0[/tex].(adsbygoogle = window.adsbygoogle || []).push({});

If we now take the Poencare group as group representing space-time symmetries and apply the same reasoning as above we will come to the relation [tex]P_{\mu}P^{\mu}|\Psi\rangle=m^2|\Psi\rangle[/tex] being the Klein-Gordon equation for free particle [tex](\Box+m^2)\Psi(x)=0[/tex].

Now, what is common to both equations is that spin is excluded, that is to say, we are for some reason prevented to take into consideration both the rotational and translational symmetry so we cannot adequatly describe spin-[tex]\frac{1}{2}[/tex] particles.

My question is, is there a way to get Dirac equation the same way Schrodinger and Klein-Gordnon can be directly obtained from symmetries or we have to follow little more complicated path? If we cannot, what prevents us? Is the reason for this that Dirac eqation is first order in derivatives? Is there a second order version of Dirac equation?

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# Obtaining Dirac equation from symmetries

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