- #1

Roni1985

- 201

- 0

## Homework Statement

it's already separable, so it's an ODE function.

X''+[tex]\lambda[/tex]*X=0 0<x<1

X(0)=-2X(1)+X'(1)=0

## Homework Equations

## The Attempt at a Solution

this is a Sturm-Liouville eigenvalue problem.

Now, I know how to solve it and everything, but I'm not sure with one thing.

when I check the case where [tex]\lambda[/tex]=0,

I get C2(-2x+1)=0

so C2 can be anything, correct ?

now what's my eigenfunction ?

X(x)=x is the eigenfunction ?

do I use the x=1/2 somewhere ?

Thanks.