One dimensional motion of a tortoise

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A tortoise runs at a speed of 0.10 m/s, while a hare runs 20 times faster, at 2.0 m/s. In a race, the hare takes a 2.0-minute break, allowing the tortoise to win by 20 cm. The tortoise's distance covered in time t is represented by the equation 0.10*t meters. The hare's distance, accounting for the rest period, is expressed as 20*0.10*(t-120) meters. To determine the race duration and length, the equation derived from the winning condition is 20*0.10*(t-120) = 0.10*t - 0.2. Solving this equation will provide the total time of the race and the distance covered.
Physicstudent
can anyone help me with this problem please--

A tortoise can run with a speed of 0.10 m/s and a hare can run 20 times as fast. in a race they both start at the same time but the hare stops to rest for 2.0 minutes. the tortoise wins by 20 cm.

how long does the race take?
what is the length of hte race?
 
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I guess the totoise runs 0.10*t and the hare 20*0.10*(t-120) meters. One little first degree equation...
 
The distance the tortoise covers in t seconds is 0.10*t meters and the distance the hare covers is 20*0.10*(t-120) meters as Sonty said. However, the condition that "the tortoise wins by 20 cm" means that, if t is the time when the tortoise crosses the finish line, then 20*0.10*(t-120)= 0.10*t- 0.2. That's the equation you need to solve.
 
thank u both
 

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