Only given displacement vector and initial speed, solve for theta

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SUMMARY

The problem involves calculating the launch angle (theta) of a ball thrown at an initial speed of 70 m/s that reaches a height of 20 m while traveling a horizontal distance of 100 m. The equations of motion used include horizontal displacement (d = V0x * t) and vertical displacement (d = V0y * t - 1/2 * g * t^2). The solution requires expressing both x and y displacements in terms of theta and time (t), leading to a system of equations that can be solved simultaneously to find theta.

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Homework Statement


A ball is thrown with a speed of 70m/s and hits the top of a wall which is 20m tall and 100m away. Find the angle that the ball was thrown at


Homework Equations


d= V0xt + 1/2 a t^2
a = Vf-V0/t
sin^2(theta) = 1 - cos^2 (theta)

The Attempt at a Solution


I found the initial velocity in terms of theta V= 70cos(theta) x + 70sin(theta) y
the part I'm stuck on is apparently we are supposed to find the time from the horizontal displacement somehow. That i am stuck on because it seems like a i have too many variables and not enough information. any help is appriciated
 
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I think you have all the information you need. You can write separate equations for the x and y displacement in terms of theta and t. This is two equations and two unknowns.
 

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