Open Electric Circuit, which statements are/is true about it

[Femme_physics]

Homework Statement

With respect to the attached drawing of an open circuit, which statement/s is/are true?

A) The circuit is open therefor no current flows in it
B) Vab = 0
C) Vab strives to infinity
D) Kirchhoff's current law does not apply on an open circuit
E) Vab = 20V
F) The voltage potential on the resistor equals 20V
G) The voltage potential on the circuit equals 0V
H) The flows in the circuit equals 1mA

The Attempt at a Solution

A) True
B) False, potential difference is about difference, not current.
C) I have a feeling that's false-- my theory is that the potential difference in terminals always equals to the potential difference in the battery.
D) No, Kirchhoff's law is always applied
E) True, based on my theory at C
F) True. I = 20/20. V = 20x1 V = 20 [V]
G) Not, that's 20. That's what we're told the difference is, it doesn't change.
H) False. It equals 1 Ampere (20 divided by 20), not miliampere.



Am I correct in everything?

 

[I like Serena]

Homework Statement

With respect to the attached drawing of an open circuit, which statement/s is/are true?

A) The circuit is open therefor no current flows in it
B) Vab = 0
C) Vab strives to infinity
D) Kirchhoff's current law does not apply on an open circuit
E) Vab = 20V
F) The voltage potential on the resistor equals 20V
G) The voltage potential on the circuit equals 0V
H) The flows in the circuit equals 1mA

The Attempt at a Solution

A) True
B) False, potential difference is about difference, not current.
C) I have a feeling that's false-- my theory is that the potential difference in terminals always equals to the potential difference in the battery.
D) No, Kirchhoff's law is always applied
E) True, based on my theory at C
F) True. I = 20/20. V = 20x1 V = 20 [V]
G) Not, that's 20. That's what we're told the difference is, it doesn't change.
H) False. It equals 1 Ampere (20 divided by 20), not miliampere.



Am I correct in everything?

Not quite:
A,B,C,D,E,G,H have the proper answers, but the reasoning isn't quite right.

In an open circuit no current flows, so I = 0.
The voltage drop over the resistor is V = I . R = 0 . R = 0
So the voltage at A and B is 20.
Kirchhoff's laws are indeed applicable.

If the circuit were closed (A and B connected), then there would be a current I = 20/20 A.
In this case the voltage drop over the resistor would be 20 V and obviously the voltage drop between A and B would be 0.
Again Kirchhoff's laws are indeed applicable.