Operational amplifier with feedback problem

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TheRedDevil18
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Homework Statement


Circuit schematic of a voltage-series feedback op-amp amplifier with source Vsig, input resistor Rin, feedback resistors R1 and R2, output resistor Rout, load RL, output current io and output voltage Vo, labelled with R1 and R2 and the output node r.


Homework Equations

The Attempt at a Solution


Handwritten notes on lined paper showing a small-signal circuit with a dashed box around a transistor amplifier stage, labels Vsig, Vi, Rid, R1, R2, Ro, RL and r, and equations for RL', Io, Vi, RA and Vo, plus beta defined as Vi over Io.

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Using the equations above, I'm not getting the right answer for beta which is 0.4926 V/A.
Is my model wrong ?
 
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The op-amp's ro should be shown in series with the controlled voltage source.
 
NascentOxygen said:
The op-amp's ro should be shown in series with the controlled voltage source.
So with a voltage source, ro is always in series ?
 
TheRedDevil18 said:
So with a voltage source, ro is always in series ?
Yes.

If you were to place a resistance in parallel with an ideal voltage source, what would be the Thévenin equivalent resistance of that combination?
 
NascentOxygen said:
Yes.

If you were to place a resistance in parallel with an ideal voltage source, what would be the Thévenin equivalent resistance of that combination?

Would it be a voltage source in series with the resistance ?, I know that a current source with a parallel resistance is equal to a voltage source in series with that resistance
 
TheRedDevil18 said:
Would it be a voltage source in series with the resistance ?
Guessing is not allowed.

Can you determine it?
 
NascentOxygen said:
Guessing is not allowed.

Can you determine it?

Would it be zero ?, I determined it by using the rules. When you have a voltage source you short it and remove the load, so that means all the current will flow through the short and not through the parallel resistor
 
TheRedDevil18 said:
Would it be zero ?, I determined it by using the rules. When you have a voltage source you short it and remove the load, so that means all the current will flow through the short and not through the parallel resistor
Right. A resistance has no effect if you erroneously add it parallel to an ideal voltage source: the effective source resistance here would stay as zero.
 
NascentOxygen said:
Right. A resistance has no effect if you erroneously add it parallel to an ideal voltage source: the effective source resistance here would stay as zero.

Ok, thanks, I'll attempt the question again